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(q^2)-(559.2562q)+34745.2021=0
We add all the numbers together, and all the variables
q^2-(+559.2562q)+34745.2021=0
We get rid of parentheses
q^2-559.2562q+34745.2021=0
a = 1; b = -559.2562; c = +34745.2021;
Δ = b2-4ac
Δ = -559.25622-4·1·34745.2021
Δ = 173786.688838
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-559.2562)-\sqrt{173786.688838}}{2*1}=\frac{559.2562-\sqrt{173786.688838}}{2} $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-559.2562)+\sqrt{173786.688838}}{2*1}=\frac{559.2562+\sqrt{173786.688838}}{2} $
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